【基础入门题】2021.12.02

根据 Pi²/8 = 1 + 1/3² + 1/5² + 1/7² + ...，编制计算Pi近似值的函数。

编程语言：包括但不限于Python
题目来源：派森特给站每日刷题频道    

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方法一：

def Pi(n):
    res = 0
    for i in range(1,n+1):
        res += 1/(2*i-1)**2
    return (res*8)**0.5

print(Pi(1000))
print(Pi(10000))
print(Pi(100000))
print(Pi(1000000))
print(Pi(10000000))

'''
3.14127432760274
3.1415608224399487
3.141589470489344
3.1415923352799697
3.1415926217577352
'''

方法二：推导式

Pi = lambda n:(8*sum(1/(2*i-1)**2 for i in range(1,n+1)))**0.5

print(Pi(1000))
print(Pi(10000))
print(Pi(100000))
print(Pi(1000000))
print(Pi(10000000))

'''
3.14127432760274
3.1415608224399487
3.141589470489344
3.1415923352799697
3.1415926217577352
'''

1000万次循环可以计算到7位有效数字。

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